x^2+22x-240x=0

Solution for x^2+22x-240x=0 equation:

x^2+22x-240x=0

We add all the numbers together, and all the variables

x^2-218x=0

a = 1; b = -218; c = 0;
Δ = b2-4ac
Δ = -2182-4·1·0
Δ = 47524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{47524}=218$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-218)-218}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-218)+218}{2*1}=\frac{436}{2}
=218
$